python - better way of handling nested list -

my_list = [ [1,2,3,4,5,6], [1,3,4],[34,56,56,56]] item in my_list:     var1,var2,var3,var4,var5,var6 = none      if len(item) ==1:           var1 = item[0]      if len(item) == 2:           var1 = item[0]           var2  = item[1]      if len(item) == 3:          var1 = item[0]          var2 = item[1]          var3 = item[2]      if len(item) == 4:         var1 = item[0]         var2 = item[1]         var3 = item[2]         var4 = item[3]     fun(var1,var2,var3,var4,var5,var6) 

i have function

def fun(var1, var2 = none, var3 = none, var4 = none, var5=none, var6= none) 

depending upon values in inner list. passing function. hope made clear.

thanks

see calls , function definitions in python documentation, specifically:

if syntax *expression appears in function call, expression must evaluate sequence. elements sequence treated if additional positional arguments....

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if syntax **expression appears in function call, expression must evaluate mapping, contents of treated additional keyword arguments....

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...a function call assigns values parameters mentioned in parameter list, either position arguments, keyword arguments, or default values. if form “*identifier” present, initialized tuple receiving excess positional parameters, defaulting empty tuple. if form “**identifier” present, initialized new dictionary receiving excess keyword arguments, defaulting new empty dictionary.

example 1

you need following, since arguments simple integers:

my_list = [[1,2,3,4,5,6],[1,3,4],[34,56,56,56]]  def func(*var):     arg in var:         print arg,     print  args in my_list:     func(*args) 

output 1

1 2 3 4 5 6  1 3 4  34 56 56 56  

example 2

the next example shows can fill in number of arguments function defaults:

my_list = [[1,2,3,4,5,6],[1,3,4],[34,56,56,56]]  def func(var1=none,var2=none,var3=none,var4=none,var5=none,var6=none):     print var1,var2,var3,var4,var5,var6  args in my_list:     func(*args) 

output 2

1 2 3 4 5 6 1 3 4 none none none 34 56 56 56 none none 

example 3

you can fill them in out-of-order ** syntax:

my_list = [dict(var1=1,var5=5,var6=6),dict(var2=2,var4=4)]  def func(var1=none,var2=none,var3=none,var4=none,var5=none,var6=none):     print var1,var2,var3,var4,var5,var6  args in my_list:     func(**args) 

output 3

1 none none none 5 6 none 2 none 4 none none