c++ - Char-array to int -

i have array char input[11] = {'0','2','7', '-','1','1','2', ,'0','0','9','5'};

how convert input[0,1,2] int 1 = 27, input[3,4,5,6] int 2 = -112 , input[7,8,9,10] int 3 = 95?

thx, jnk

you can use combination of strncpy() extract character range , atoi() convert integer (or read this question more ways convert string int).

int extract(char *input, int from, int length) {   char temp[length+1] = { 0 };   strncpy(temp, input+from, length);   return atoi(temp); }  int main() {   char input[11] = {'0','2','7','-','1','1','2','0','0','9','5'};   cout << "heading: " << extract(input, 0, 3) << endl;   cout << "pitch:   " << extract(input, 3, 4) << endl;   cout << "roll:    " << extract(input, 7, 4) << endl; } 

outputs

heading: 27 pitch:   -112 roll:    95 

http://ideone.com/suutl