regex - java regular expression to match file path -

i trying out create regular expression match file path in java like

c:\abc\def\ghi\abc.txt

i tried ([a-za-z]:)?(\\[a-za-z0-9_-]+)+\\? , following code

import java.util.regex.pattern;    public class retester {  public static void main(string arhs[]){      string regularexpression = "([a-za-z]:)?(\\[a-za-z0-9_-]+)+\\?";      string path = "d:\\directoryname\\testing\\abc.txt";      pattern pattern = pattern.compile(regularexpression);      boolean ismatched = pattern.matches(regularexpression,path);     system.out.println(path);     system.out.println(pattern.pattern());     system.out.println(ismatched);  }  } 

however it's giving me , false result . pls me .

thanks

java using backslash-escaping too, know, need escape backslashes twice, once java string, , once regexp.

"([a-za-z]:)?(\\\\[a-za-z0-9_.-]+)+\\\\?" 

your regexp matched literal '[-za-z0-9_-' string, , literal '?' @ end. added period in there allow 'abc.txt'..

that said, consider using mechanism determine valid file names, there different schemes (i.e. unix). java.util.file throw exception if path invalid, might alternative, although don't using exceptions control flow...